1² x 1/4m² x (-6)ml find the product

CaptRespect asked Apr 22, 2022

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CaptRespect asked Apr 22, 2022

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12 votes

$\\ \sf\longmapsto 1^2* (1)/(4)m^2$

$\\ \sf\longmapsto (1)/(4)m^2$

Now

$\\ \sf\longmapsto (1)/(4)m^2* -6m$

$\\ \sf\longmapsto (-6)/(4)m^3$

$\\ \sf\longmapsto (-3)/(2)m^3$

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