Question

-If sulfuric acid (H2SO4) reacts with 29 grams of sodium chloride (NaCl), how  many grams of hydrochloric acid (HCl) are produced?  H2SO4   +        NaCl     ­­­­>          HCl    +     Na2SO4

- In the same reaction, how much salt (NaCl) is needed to produce 4.0 moles of  sodium sulfate (Na2SO4)? 

- In the same reaction, if you started with 100 moles of sulfuric acid (H2SO4), how  many moles of hydrochloric acid (HCl) could you produce?​

Answer 1

Step-by-step explanation:

mole = mass/molar mass

mole of Nacl = mass/mm

molar mass of Nacl = Na + Cl = 23+35=58

mole of NaCl = 29/58

mole of NaCl = 0.5mol

H2SO4 + NaCl ====> HCl + Na2SO4

1. 1. 1. 1

since mole of NaCl is 0.2mol then mole of HCl is also 0.2mol since they are all in the same ratio

mole of HCl = Mole of NaCl = 0.5mol

mass of HCl = ?

molar mass of HCl = H + Cl = 1+ 35=36

mole of HCl = mass /molar mass

0.5= mass/36

mass = 0.5×36 = 18 grams