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the area of the rectangular city park is 25/24 square miles. the length of the park is 5/9 mile. what is the width,in mils, of the park

User Carlos Nunez
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1 Answer

19 votes
19 votes

Answer:

  • A rectangle's area is Length * Width [Let x = rectangle's width]
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles)
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles)
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5)
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out]
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out]
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] The width is 5/6 miles
  • A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] The width is 5/6 miles
  • Just to check:
  • (5/9)*(5/6) = 25/54
User Eirini
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