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Lactose, C12H22O11, is a naturally occurring sugar found in mammalian milk. A 0.335 M solution of lactose in water has a density of 1.0432 g/mL at 20 o C. What is the concentration of this solution in the following units?

i) mole fraction
ii) molality
iii) mass percent

1 Answer

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Final answer:

To find the concentration of the lactose solution in different units, we can use the given information. The mole fraction can be calculated by dividing the moles of lactose by the total moles. The molality can be calculated by dividing the moles of lactose by the mass of water in kilograms. The mass percent can be calculated by dividing the mass of lactose by the mass of the entire solution and multiplying by 100%.

Step-by-step explanation:

To find the concentration of a lactose solution in different units, we can use the given information. First, we need to calculate the molarity of the solution using the formula: Molarity (M) = moles of solute / volume of solution in liters. Since we have the density of the solution, we can convert the volume in milliliters to liters. Next, we can find the molality of the solution using the formula: Molality (m) = moles of solute / mass of solvent in kilograms. Finally, to find the mass percent of the solution, we can use the formula: Mass percent = (mass of solute / mass of solution) x 100%.

i) Mole fraction:

To find the mole fraction of lactose, we need to calculate the moles of lactose and the total moles of both solute and solvent. The mole fraction of lactose can be calculated by dividing the moles of lactose by the total moles.

ii) Molality:

To find the molality, we need to calculate the moles of lactose and the mass of water in the solution. The molality can be calculated by dividing the moles of lactose by the mass of water in kilograms.

iii) Mass percent:

To find the mass percent, we need to calculate the mass of lactose and the mass of the entire solution. The mass percent can be calculated by dividing the mass of lactose by the mass of the entire solution and multiplying by 100%.

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