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28 votes
28 votes
Find the third degree polynomial function that has an output of 40 when x = 1, and has zeros - 19 and -i?

User OneSneakyMofo
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1 Answer

8 votes
8 votes

Answer:

f(x) = x³ + 19x² + x + 19

Explanation:

Zeros: -19 , -i, complex conjugate root: +i

Function: (x+19)(x+i)(x-i) = 0

(x + 19) (x² - i²) = (x + 19) ( x² + 1) = x³ + 19x² + x + 19

check: when x = 1

f(1) = 1 + 19 + 1 +19 = 40

User Sabarish
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