Question

ALGEBRA 2


9) Solve using elimination.
3a = -5b-2
10b=1-6a

Answer 1

No solution.

Explanation:

Solving using elimination method:

3a = - 5b - 2

3a + 5b = -2 ------------------(I)

10b = 1 - 6a

6a + 10b = 1 --------------------(II)

`\sf (a_1)/(a_2)= (3)/(6)=(1)/(2)\\\\(b_1)/(b_2)=(5)/(10)=(1)/(2)\\\\(c_1)/(c_2) = (-2)/(1)`

`\sf (a_1)/(a_2)=(b_1)/(b_2)\\eq (c_1)/(c_2)`

So, this system of linear equations are two parallel lines and has no solution.