Question

Write the equation of a line perpendicular to the line 2x + 3y = 12 and passes through (9, -2). (fractions go in one box - use lower case letters)

Answer 1

Explanation:

Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)

Rewrite the equation as y = (2/3)x - 4 This has slope 2/3

A perpendicular line will have slope -3/2 so the equation of a perpendicuar line is y = -(3/2)x + c where c is a constant found from the fact that the line must go through point (16, -7).

-7 = -(3/2).16 + c

c = 24 - 7

c = 17

Hence perpendicular line has equation y = -(3/2)x + 17