Let:
P be the perimeter of the pool
L = length of the pool
B = breadth of the pool
Given
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P = 2L + 2B = 154 m
L = 2 + 2B
P = 2(2 + 2B) + 2B ……. Substitute
154 = 4 + 4B + 2B ……. Distribution
154 = 4 + 6B ……… Add like terms
154 - 4 = 6B
150 = 6B
150/6 = 6B/6 …….. Divide both sides by 6
25 = B …. Breadth
L = 2 + 2B
L = 2 + 2(25) = 2 + 50
L = 52
Length = 52 and breadth = 25