Question

An object oscillates as it moves along the

x-axis. Its displacement varies with time
according to the equation
x = 4 sin(pi(t)+ pi/2)
where t = time in seconds and
x = displacement in meters
What is the displacement between t = 0
and t = 1 second?
[?] meters

Answer 1

The displacement between t = 0 and t = 1 second is -4 meters.

Step-by-step explanation:

The displacement of an object oscillating along the x-axis is given by the equation x = 4 sin(pi(t)+ pi/2), where t is the time in seconds and x is the displacement in meters.

To find the displacement between t = 0 and t = 1 second, we substitute these values into the equation:

x(1) = 4 sin(pi(1)+ pi/2) = 4 sin(pi + pi/2) = 4 sin(3*pi/2) = 4 * -1 = -4 meters.

Therefore, the displacement between t = 0 and t = 1 second is -4 meters.