Question

This is my question…

Answer 1

otal number of cCustomer = 11 + 9 + 11 + 5 + 5 + 1 + 3 = 45

Let A denotes the event that the Customer waited for at least 12 minutes

Let B denotes the event that the Customer waited between 8 and 15 minutes

`\begin{gathered} n(A)=5+5+1+3=14 \\ n(B)=11+5=16 \\ n(A\cap B)=5 \end{gathered}`

We want to find

`p(A\cup B)`
`\begin{gathered} p(A\cup B)=p(A)+p(B)-p(A\cap B) \\ p(A\cup B)=(14)/(45)+(16)/(45)-(5)/(45) \\ p(A\cup B)=(25)/(45) \\ p(A\cup B)=(5)/(9) \\ p(A\cup B)=0.556\text{ (to the nearest thousandth)} \end{gathered}`

hus, the probability is 0.556

Option D