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Using the given sample data, calculate the following measures of dispersion, to one decimal place.

Using the given sample data, calculate the following measures of dispersion, to one-example-1
User Vicctor
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Answer:

Range = 15

Variance = 24.5Explanations

Standard deviation = 5.0

The formula for calculating the range is expressed as:

Range = Highest value - Lowest value

Range = 24 - 9

Range = 15

Calculate the variance

The formula for calculating the variance is expressed as:


Variance=\frac{\sum(x-\overline{x})^2}{n-1}

Find the mean


\begin{gathered} mean=(9+13+15+18+19+20+24)/(7) \\ mean\text{ }\overline{x}=(118)/(7)=16.9 \end{gathered}

Determine the variance


\begin{gathered} S^2=((9-16.9)^2+(13-16.9)^2+(15-16.9)^2+(18-16.9)^2+(19-16.9)^2+(20-16.9)^2+(24-16.9)^2)/(7-1) \\ S^2=(146.9)/(6) \\ S^2\approx24.5 \end{gathered}

Determine the standard deviation


\begin{gathered} S=√(variance) \\ S=√(24.5) \\ S\approx5.0 \end{gathered}

User Volox
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