Question:
On a circle of radius 6 feet, what angle would subtend an arc of lenght 5 feet?
nswer:
he frormula for the lenght of arc (s) given an angle theta (in radians) and a radius R is:

We'll just have to clear theta from this equation, and convert it to degrees.

Therefore, the angle that would subtend an arc of lenght 5 feet on a circle of radius 6 feet is 47.74°