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Im stuck on this question-example-1

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a) g(3) = -182

b) g(0) = 7

c) g(-1) = 70

Step-by-step explanation:
\begin{gathered} \text{Given:} \\ g(x)\text{ = }7\text{ - 63x} \end{gathered}

a) g(3): To get this, we will substitute 3 for x in the function g(x)


\begin{gathered} \text{x = 3} \\ g(3)=\text{ 7 - 63(3) = 7 - 189} \\ g(3)\text{ = }-182 \end{gathered}

b) g(0): To get this, we will substitute 0 for x in function g(x)


\begin{gathered} x\text{ = 0} \\ g(0)\text{ = 7 - 63(0) = 7 - 0} \\ g(0)\text{ = 7} \end{gathered}

c) g(-1): To get this, we will substitute -1 for x in function g(x)


\begin{gathered} x\text{ = -1} \\ g(-1)\text{ = 7 - 63(-1)} \\ mu\text{ltiplication of same signs give positive sign} \\ g(-1)\text{ = 7 + 63} \\ g(-1)\text{ = 70} \end{gathered}

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