22.5g of potassium carbonate is dissolved in water and then mixed with excess aluminum nitrate. How many moles of dried precipitate should be formed?

Question

asked Jan 15, 2023 210k views

1 Answer

Nazgul · Answer 1 · 2023-01-21T22:02:38+0000

Explanations

$3K_2CO_3(aq)+2Al_2\operatorname{\lparen}NO_3)_3+3H_2O\rightarrow2Al(OH)_3+3CO_2+6KNO_3$

Given the following

Mass of potassium carbonate = 22.5grams

Determine the moles of potassium carbonate

Moles of potassium carbonate = mass/molar mass

22.5/138.205|

= 0.1628moles

Since the precipitate formed is aluminum hydroxide, hence the mole of precipitate formed if 3moles off K2CO3 produce 2moles of Al(OH)3 is given as:

$\begin{gathered} mole\text{ of Al\lparen OH\rparen}_3=(2)/(3)*0.1628 \\ mole\text{ of Al\lparen OH\rparen}_3=0.1085moles \end{gathered}$

Hence the moles of dried precipitate should be formed