Question

1. A car begins at a speed of 3m/s and accelerates at 2m/s² over a distance of 40m,

calculate the final speed of the car.

Answer 1

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \: v = 13 \:\: m/s`

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`\large \tt Solution \: :`

• 
  `\texttt{Initial speed of the car (u) = 3 m/s}`

• 
  `\texttt{final speed of the car (v) = ??}`

• 
  `\texttt{acceleration of the car (a)= 2 m/s²}`

• 
  `\texttt{distance covered in that time (s) = 40 m}`

By third equation of motion :

`\qquad \tt \rightarrow \: {v}^(2) = {u}^(2) + 2as`

`\qquad \tt \rightarrow \: {v}^(2) = (3) {}^(2) + 2(2)(40)`

`\qquad \tt \rightarrow \: {v}^(2) = 9 + 160`

`\qquad \tt \rightarrow \: {v}^(2) = 169`

`\qquad \tt \rightarrow \: v = 169`

`\qquad \tt \rightarrow \: v = 13`

so, speed of the car after that time is : 13 m/s

Answered by : ❝ AǫᴜᴀWɪᴢ ❞