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Find the sum of the first 16 terms of the arithmetic sequence: 8,11,14,17,20,...

User Tomeduarte
by
8.1k points

1 Answer

1 vote

Answer:

S₁₆ = 488

Explanation:

the sum to n terms of an arithmetic sequence is


S_(n) =
(n)/(2) [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

here a₁ = 8 and d = a₂ - a₁ = 11 - 8 = 3 , then

S₁₆ =
(16)/(2) [ (2 × 8) + (15 × 3) ]

= 8(16 + 45)

= 8 × 61

= 488

User Michael McCauley
by
7.5k points

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