Question

What in the world how do you solve this?

Answer 1

B

Explanation:

using the rule of radicals

•
`\sqrt[n]{x}` ÷
`\sqrt[n]{y}` =
`\sqrt[n]{(x)/(y) }`, then

32
`\sqrt[8]{18y}` ÷ 8
`\sqrt[8]{3y}`

=
`(32)/(8)` ×
`\sqrt[8]{(18y)/(3y) }` ( cancel 18y and 3y by 3y )

= 4 ×
`\sqrt[8]{6}`

= 4
`\sqrt[8]{6}`