Question

Find the equation of the line.

a line that is perpendicular to the graph of y=-3x +2 and
contains the point (3,-3)

Answer 1

Answer: y = -3x + 6

Explanation:

If it is perpendicular to the line -3x + 2, then it's slope should also be -3.

The standard form of a line is y = mx + b. As our slope is -3, we have that our line is y = -3x+b. Now, let's put the given point into the line. x = 3 and y = -3, so -3 = -3*3 + b. Hence, b = -3+9 = 6. The equation of the line is y = -3x + 6.