Question

A student rolls a soccer ball down a ramp. the ball accelerates from rest to 2.0 m/s in 3.5 seconds. what was the acceleration of the ball as it rolled down the ramp? (4b)

Answer 1

The acceleration of the soccer ball as it rolled down the ramp was 0.571 m/s², calculated using the formula for acceleration (a = (v - u) / t).

Step-by-step explanation:

The student rolled a soccer ball down a ramp and it accelerated from rest to 2.0 m/s in 3.5 seconds. The question is to find the acceleration of the ball as it rolled down the ramp. This is a physics problem involving the kinematic equations of motion.

To find the acceleration, we can use the equation of motion:

a = (v - u) / t

where a is acceleration, v is final velocity, u is initial velocity (which is 0 since it started from rest), and t is time.

Using the values from the question:

a = (2.0 m/s - 0 m/s) / 3.5 s = 0.571 m/s²

The acceleration of the ball was 0.571 m/s².

Answer 2

Use kinematic equation v=vo + at. plug in your numbers, vo is 0, v=2.0 and t is 3.5. Solve for acceleration and you should get 0.57 m/s^2