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Need help with this question ​-example-1
User JLoppert
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2 Answers

16 votes
16 votes

Answer:

...

Explanation:

User Jeiwan
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11 votes
11 votes

Answer:

Explanation:

A) ∠1 = ∠2 {Alternate angles are equal}

6x + y - 4 = x - 9y + 1

6x + y = x - 9y + 1 + 4

6x + y = x - 9y + 5

6x - x + y + 9y = 5

5x + 10y = 5

Divide the entire equation by 5

x + 2y = 1 -------------(I)

∠2 + ∠3 = 180 {Linear pair}

x - 9y + 1 + 11x + 2 = 180

x + 11x - 9y = 180 - 2 - 1

12x - 9y = 177

Divide the whole equation by 3

4x - 3y = 59 -------------(II)

B) Multiply equation (I) by 3 and multiply equation (II) by 2. Thus y will be eliminated and we can find the value of x.

(I)* 3 3x + 6y = 3

(II)*2 8x - 6y = 118 {Now add}

11x = 121

x = 121/11

x = 11

Plugin x = 11 in equation (I)

11 + 2y = 1

2y = 1 -11

2y = -10

y = -10/2

y = -5

C) ∠1 = 6x + y - 4

= 6*11 - 5 - 4

= 66 - 5 - 4

= 57

∠2 = x - 9y + 1

= 11 -9*(-5) + 1

= 11 + 45 + 1

= 57

∠3 = 11x + 2

= 11*11 + 2

= 121 + 2

= 123

User Overcomer
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