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If ƒ(x) = x/2 −2 and g(x) = 2x² + x−3, find (ƒ +g)(x).

A. 2x² + 3x-6
B. 2x² - +1
C. ²-6
D. 2x²+2x+1​

User Johndt
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1 Answer

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(f+g)(x)=f(x)+g(x)\\\\=(x)/(2)-2+2x^2 +x-3\\\\=2x^2 +(3)/(2)x-5

User Lekksi
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