Question

An airplane during departure has a constant acceleration of 3 m / s².

a. What is the speed that the plane reaches in 4 s?
b. If the plane passes at a flight point of
at a speed of 20 m / s, what is the speed 8 s later?​

Answer 1

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = v - u

t

3 = v - 20

8

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.