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Solve 3x2 4x = 2. quantity of 2 plus or minus square root of 10 all over 6 quantity of negative 2 plus or minus 2 square root of 10 all over 3 quantity of negative 2 plus or minus square root of 10 all over 3 quantity of negative 4 plus or minus square root of 10 all over 3

User Weston C
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1 Answer

7 votes

Main Answer:


x=(-2\±√(10))/(3)

Step-by-step explanation:

The given equation is,


3x^(2) +4x=2

The

The quadratic formula to find the value of x for the equation
ax^(2) +bx+c=0 is,


x=\frac{-b\±\sqrt{b^(2)-4ac}}{2a}

The values are,

a = 3, b = 4, c = -2

Now, substitute the values of a, b and c


x=\frac{-4\±\sqrt{(4)^(2)-4(3)(-2)}}{2(3)}


x=(-4\±√(16-12(-2)))/(6)


x=(-4\±√(40))/(6)


x=(-4\±2√(10))/(6)


x=(2(-2\±√(10)))/(6)


x=(-2\±√(10))/(3)

User Jorge Rivera
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