Answer: 3.3 kg of Cu, 1.7kg of Sn
I abbreviate copper as Cu and tin as Sn.
Explanation:
For 5 kg of $7.05$/kg bronze: Let x be the mass of Cu. The mass of Sn would be 5-x.
Multiply these two masses by their respective element cost.
Cu = ($6.20/kg)x [The total value of copper in 5 kg of bronze]
Sn = ($8.70/kg)(5-x) [The total value of tin in 5 kg of bronze]
We know that:
($6.20/kg)x + ($8.70/kg)(5-x) = $7.05
Solve for x. I get
x= 3.3 kg of Cu
5-x = 1.7kg of Sn
==
Check the result for 5 kg of bronze:
(3.3 kg of Cu)*($6.20/kg) = $20.46 cost of Cu
(1.7kg of Sn)*($8.70/kg) = $14.79 cost of Sn
Thus, the total cost for 5kg of bronze is $35.25. That makes it $7.05/kg.