Question

write the equation of the line in point-slope form, that is parallel to y=5/2x + 1 and passes through the point (-3,1)

Answer 1

`\sf y = (5)/(2)x +(17)/(2)`

Explanation:

`\sf y =(5)/(2)x+1`

m= 5/2

Parallel lines have same slope.

Slope y-intercept form: y = mx +b

Here, m is the slope and b is the y-intercept

`\sf y = (5)/(2)x + b`

Point (-3,1) passes through the required line. Substitute (-3,1) in the above equation and find 'b'.

`\sf 1 = (5)/(2)*(-3)+b\\\\1 =(-15)/(2)+b\\\\`

`\sf 1 +(15)/(2)=b\\\\(2+15)/(2)=b\\\\\\ \boxed{b= (17)/(2)}`

`\sf \bf y = (5)/(2)x+(17)/(2)`