Question

Write an equation the describes the line passing through point (-2,8) with slope 4/5

Answer 1

The equation of the line passing through the point (-2,8) with a slope of 4/5 is y = (4/5)x + 48/5.

Step-by-step explanation:

The equation of a line in slope-intercept form is y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slope is 4/5 and the line passes through the point (-2,8). To write the equation, we substitute the values into the equation.

y = (4/5)x + b

Using the coordinates of the point (-2,8), we can substitute them into the equation to solve for the y-intercept:

8 = (4/5)(-2) + b

8 = -8/5 + b

To solve for b, we subtract -8/5 from 8:

40/5 + 8/5 = b

b = 48/5

Therefore, the equation of the line passing through the point (-2,8) with a slope of 4/5 is y = (4/5)x + 48/5.

Answer 2

point-slope form:
`y-8=(4)/(5)(x+2)`

Step-by-step explanation:

hope this helps :)