Answer:
A
Explanation:
Given a function f(x) where the first derivative with respect to x evaluated in two equals
f'(2)=1/2
The slope of the tangent line is
mt=1/2
Therefore, the slope of the normal line is
mn=-1/(1/2)
mn=-2
Evaluating the given point in the general form
y-y1=m(x-x1)
y-(-1)=-2(x-2)
y+1=-2x+4
y=-2x+3