Question

Find the equation of the line passing through points (6,0) and (-1,14).

Oy = 6x
y = -2x + 12
y = -2x + 14
y = 2x + 10

Answer 1

y = - 2x + 12

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (6, 0 ) and (x₂, y₂ ) = (- 1, 14 )

m =
`(14-0)/(-1-6)` =
`(14)/(-7)` = - 2 , then

y = - 2x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (6, 0 )

0 = - 12 + c ⇒ c = 0 + 12 = 12

y = - 2x + 12 ← equation of line