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consider the line -7x-6y=5 find the equation of the line that is parallel to this line and passes through the point (3,5)​

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Answer:

Equation of line is given as y = mx + c, where m is the gradient and c is the y-intercept.

First rearrange -7x - 6y = 5 into y = mx + c form.

-6y = 7x + 5

y = -7/6x - 5/6

Equation of line is y = -7/6x + c

Substitute the coordinates (3,5) into equation to find c.

5 = -7/6(3) + 3

c = 17/2

Hence the equation of line is y = -7/6x + 17/2

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