Question

Helpp the topic is about limits

Answer 1

Since we want to find the value of k where the limit exists, set both equations equal to each other. Then substitute x = -1 in for each equation to find k.

`kx - 3 = {x}^(2) + k`

1. Set both equations equal.

`- k - 3 = 1 + k`

2. Substitute x = -1.

`- 3 = 1 + 2k`

3. Solve for k by adding k to both sides. Continue the process of solving the equation.

`- 4 = 2k`

`k = - 2`

Thus, k = -2. Check by graphing the function.