Question

A triangle has vertices at A (-2, -2), B (-1, 1), and C (3, 2). Which of the following transformations produces an image with vertices A' (2, -2), B' (1, 1), and C' (-3, 2)?

O (x, y) -> (x, - y)
O (x, y) -› (-y, x)
O(x,y) → (-x,y)
O (x, y) -> (y, -x)

Answer 1

Mackenzie the answer is the 3rd option:)

Explanation:

Answer 2

`(x, y) \rightarrow (-x, y)`

(Option 3)

Explanation:

Let's take into account ΔABC.

A(-2, -2) B(-1, 1) C(3, 2)

This process is entirely trial and error. Try out the different transformations and see which one results the image from the preimage.

In this case, our transformation is (-x, y). Let's put this into trial and error:

`A(-2, -2) \rightarrow A'(2, -2)\\B(-1, 1) \rightarrow B'(1, 1)\\C(3, 2) \rightarrow C'(-3, 2)`

Simply, the values we got for the image is the same as provided in the question. So we know that option 3 is the right answer.