Answer:
V = 11 +3j volts
Explanation:
You want the voltage in a circuit with current (3 -j) and impedance (3 +2j).
Voltage
The voltage is the product of current and impedance.
V = (3 -j)(3 +2j) = 3(3 +2j) -j(3 +2j)
= 9 +6j -3j -2j² = 9 -2(-1) +(6 -3)j
= 11 +3j
The voltage is V = 11 +3j.
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Additional comment
In electronics, the letter j is used in place of the letter i to mean √(-1). This is because i means something else. (Here, i is used for "impedance." It is conventionally used for "current.")
The multiplication is carried out as though the values were polynomials. In the end, j² is replaced by -1.
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