5sin^2x-3sinx=0 solve in degrees solve in the interval 0°\leqx\leq360°

Question

`5sin^2x-3sinx=0`

solve in degrees
solve in the interval 0°
`\leq`x
`\leq`360°

Answer 1

`5sin^2(x)-3sin(x)=0\implies sin(x)[5sin(x)-3]=0 \\\\[-0.35em] ~\dotfill\\\\ sin(x)=0\implies x=sin^(-1)(0)\implies x= \begin{cases} 0\\ 180^o\\ 360^o \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 5sin(x)-3=0\implies 5sin(x)=3\implies sin(x)=\cfrac{3}{5} \\\\\\ x=sin^(-1)\left( \cfrac{3}{5} \right)\implies x\approx \begin{cases} \stackrel{I~Quadrant}{36.87^o}\\\\ \stackrel{II~Quadrant}{143.13^o} \end{cases}`