1. How many grams would 3.07 moles of FeCl3 be?

asked Oct 23, 2023 167k views

1 vote

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3 votes

Answer:

497.97 g

Step-by-step explanation:

Fe weights 55.845 g

Cl weights 35.453g

1 mole FeCl3 = 55.845 + 3(35.453) = 162.204 g

=> 3.07 moles = 3.07(162.204) = 497.96628 or 497.97 g

Maddy RS answered Oct 28, 2023

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