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2 votes
What is the distance between (8,-3) and (4, -7)?

Choose 1 answer:
6
9
√32
√42

1 Answer

4 votes

Answer:

C. 32

Explanation:

Use the distance formula.

Distance:


\Rightarrow \sf{√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)}

y₂=(-7)

y₁=(-3)

x₂=4

x₁=8


\sf{√(\left(4-8\right)^2+\left(-7-\left(-3\right)\right)^2)}

Solve.

Use the order of operations.

PEMDAS stands for:

  • Parentheses
  • Exponents
  • Multiply
  • Divide
  • Add
  • Subtract

Do parentheses first.

(4-8)=-4


\sf{\left(-4\right)^2+\left(-7-\left(-3\right)\right)^2}

-7-(-3)=-7+3

-7+3=-4


\sf{\left(-4\right)^2+\left(-4\right)^2}

Do exponents.


\sf{(-4)^2=4^2=4*4=16}

Then, you add.

16+16


\Rightarrow \boxed{\sf{32}}

Therefore, the correct answer is C. 32.

User Subhojit
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