Question

Write the equation of the line passing through the points (15,4) and (-3,-3) please helppp 10 points pleaseeeeeeeeeee

Answer 1

Answer:
`y = (1)/(3)x-2`

This is the same as writing y = (1/3)x - 2

Slope = 1/3

y intercept = -2

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Step-by-step explanation:

We first need to determine the slope

`m = (y_2-y_1)/(x_2-x_1)\\\\m = (-3-3)/(-3-15)\\\\m = (-6)/(-18)\\\\m = (1)/(3)\\\\`

Then we'll use this value of m, along with (x,y) = (15,3), to determine the y intercept b value.

`y = mx+b\\\\3 = (1/3)(15)+b\\\\3 = 5+b\\\\3 - 5 = b\\\\-2 = b\\\\b = -2`

You could use the other point (-3,-3) as well

`y = mx+b\\\\-3 = (1/3)(-3)+b\\\\-3 = -1+b\\\\-3 +1 = b\\\\-2 = b\\\\b = -2`

Either way, we end up with the same y intercept. You don't need to show both sets of steps when computing b. You only need to pick one set of steps.

Since m = 1/3 and b = -2, we go from y = mx+b to y = (1/3)x - 2 which is the same as writing
`y = (1)/(3)x-2`

Answer 2

y = 7/18 - 11/6

Step-by-step explanation:

y2 - y1 / x2 - x1

-3 - 4 / -3 - 15

-7/-18

= 7/18

y = 7/18x + b

4 = 7/18(15) + b

4 = 35/6 + b

-11/6 = b