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2 votes
Fully factorise

12x^3 + 38x^2 - 14x

User Darrick
by
4.3k points

2 Answers

4 votes

Answer:


2x(3x-1)(2x+7)

Explanation:


12x^3+3x^2-14x\\

Factor out common factor: (2x)


=2x(6x^2+19x-7)

Factor
6x^2+19x-7


= 2x(3x-1)(2x+7)

Hope this helps! :) Sorry for the late reply

User Bhakta
by
4.9k points
5 votes

Answer:

2x(2x + 7)(3x - 1).

Explanation:

12x^3 + 38x^2 - 14x

= x(12x^2 + 38x - 14)

= 2x(6x^2 + 19x - 7)

To factor the expression in the parentheses we need 2 numbers whose product is (6 * -7) = - 42 and whose sum = +19.

These are +21 and - 2.

So, we write:

6x^2 - 2x + 21x - 7

= 2x(3x - 1) + 7(3x - 1)

= (2x + 7)(3x - 1)

So, the answer is 2x(2x + 7)(3x - 1).

User Inteoryx
by
4.1k points