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5. A rocket is launched from atop a 68-foot cliff with an initial velocity of 139 feet per

second. The height of the rocket t seconds after launch is given by the equation
h=-16t² + 139t+ 68. How long after the rocket is launched will it be 12 feet from the
ground? Round to the nearest hundredth of a second.

User The Swine
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1 Answer

3 votes

Answer: Its t=

32

23673−64h

+139

Explanation:

User Noctis
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