Question

I really need help I hate Sparx maths

Answer 1

`x=(1)/(5), \quad y=6`

Explanation:

Given equations:

`\begin{cases}y=10x+4\\2y+5x=13\end{cases}`

To solve the given equations by substitution, substitute the first equation into the second equation and solve for x:

`\begin{aligned}\textsf{Equation 2}: \quad 2y+5x&=13\\\\y=10x+4 \implies 2(10x+4)+5x&=13\\20x+8+5x&=13\\25x+8&=13\\25x+8-8&=13-8\\25x&=5\\(25x)/(25)&=(5)/(25)\\x&=(1)/(5)\end{aligned}`

Substitute the found value of x into the first equation and solve for y:

`\begin{aligned}\textsf{Equation 1}: \quad y &=10x+4\\\\x=(1)/(5) \implies y&=10\left((1)/(5)\right)+4\\y&=(10)/(5)+4\\y&=2+4\\y&=6\end{aligned}`

Therefore, the solution to the equations is:

`x=(1)/(5), \quad y=6`