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What amount of pure acid must be added to 400 mL of a 30% acid solution to produce a 75% acid solution?

1 Answer

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Explanation:

pure acid is a 100% acid solution.

x = ml of 100% solution

1×x + 0.3×400 = 0.75×(400 + x)

x + 120 = 300 + 0.75x

0.25x = 180

x = 720 ml

we must add 720 ml of pure acid to the 400 ml of 30% solution to create a 75% solution (1,120 ml in total).

User Ala Varos
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