Question

What amount of a 60% acid solution must be mixed with a 45% solution to produce 600 mL of a 50% solution?

Answer 1

Explanation:

x = ml of the 60% solution

y = ml of the 45% solution

x + y = 600

and therefore

x = 600 - y

0.6x + 0.45y = 0.5×600

we use the above identity in this equation :

0.6(600 - y) + 0.45y = 300

360 - 0.6y + 0.45y = 300

60 - 0.15y = 0

60 = 0.15y

y = 400 ml

x = 600 - y = 600 - 400 = 200 ml