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What is an equation of the line that passes through the points (5, 0) and
-2, -3)?

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Answer:

Equation of line is given as y = mx + c, where m is the gradient and c is the y-intercept.

Find gradient of the line first.

Formula of gradient is given as y2-y1 ÷ x2-x1 or y1-y2 ÷ x1-x2, where x and y are the coordinates of the points.

Gradient = (-3-0) ÷ (-2-5) = 3/7

Eqn is y = 3/7x + c

Substitute either one of the coordinates into the equation to find c.

0 = 3/7(5) + c

c = -15/7

Hence, the equation of the line is y = 3/7x - 15/7

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