The line with a slope of 4, passing through (-2,1), is expressed in point-slope form as "y = 4x + 9." The slope-intercept form is "y = 4x + 9."
The point-slope form of a linear equation is given by "y - y1 = m(x - x1)," where (x1, y1) is a point on the line, and m is the slope.
Given that the slope m is 4 and the line passes through the point (-2, 1), we can substitute these values into the point-slope form equation:
y - 1 = 4(x - (-2))
Simplifying further:
y - 1 = 4(x + 2)
Distributing 4 on the right side:
y - 1 = 4x + 8
Now, isolate y by adding 1 to both sides:
y = 4x + 9
So, the equation of the line in point-slope form is "y = 4x + 9."