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If the output work is 500 J and the input work is 380 J, what is the machine efficiency?

User Pls
by
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1 Answer

4 votes

Answer:

Therefore machine efficiency is 131.6%.

Step-by-step explanation:

Data

work output = 500J

work input = 380J

M.E = ?

M.E = work output/work input × 100%

M.E = 500J/380J × 100%

M.E = 131.6%

Therefore machine efficiency is 131.6%.

User Fyodor
by
4.7k points