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(x-5)^2/8+(y+1)^2/32=1 Solve for the four vertices
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(x-5)^2/8+(y+1)^2/32=1
Solve for the four vertices

User Ed Stephenson
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1 Answer

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Answer:

i Used the standard form to find the vertices.

Vertex

1: (5,−1+4√2)

Vertex

2: (5,−1−4√2)

Explanation:

User Alyssia
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