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Find the 62nd term of the arithmetic sequence-27,-21,-15

1 Answer

4 votes

Explanation:

For Arithmetic Sequence

Tn = a + (n -- 1)d

Where Tn = the no of nth term

a = First number

n = nth term

d = common difference

a = --27, T2 = --21

d = second term -- first term

d = --27 -- (--21)

d = --27 + 21 = --6

a = --27, n = 62, d = --6, T62 = ?

Tn = a + (n -- 1)d

T62 = --27 + (62 -- 1)×--6

T62 = --27 + (61 × --6)

T62 = --27 + (--366)

T62 = --27 -- 366

T62 = --393

User Aluan Haddad
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