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Graph the solution to this system of inequalities in the coordinate plane.

3y > 2x + 12
2x + y< -5

User Maxbellec
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1 Answer

28 votes
28 votes

Answer:

The vertices of both where they cross show (-4,1)

Explanation:

3y > 2x + 12

x < 3(y - 4) / 2

y > 2 (x + 6) / 2

2x + y< -5

= x> -5

set = together

x < 3(y - 4) / 2 shows dotted ascending line attached through x=-6

This means x=--6 y = 0

x>-5 shows boundary dotted vertical line through -5

this means x = -5 y = 0

If it had been x ≥ -5 it would have been solid boundary line.

The area within the dotted lines create a right angle triangle where the far left angle shows ascends to (-6, 0) and crosses y at 0,4 however the shaded area will not got hat far and stop at -4,0 and the area below.

As seen attached when both are plotted with dash dotted boundary lines.

The vertices of both show (-5,1)

Graph the solution to this system of inequalities in the coordinate plane. 3y &gt-example-1
Graph the solution to this system of inequalities in the coordinate plane. 3y &gt-example-2
User Helene
by
2.5k points