1 Answer

Ville Laurikari · Answer 1 · 2023-12-03T07:54:02+0000

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:4\pm c$

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$\large \tt Solution \: :$

The given expression is :

$\qquad \tt \rightarrow \: 5 - |c + 1|$

$\qquad \tt \rightarrow \: 5 - 1 - |c|$

[ as 1 is a positive number, it can come out of modulus function as it is ]

$\qquad \tt \rightarrow \:4- |c|$

Now, there are two cases possible.

Case 1 :

$\qquad \tt \rightarrow \: 4- c$

[ if c is a positive number, it will come out of modulus as it is ]

Case 2 :

$\qquad \tt \rightarrow \: 4 - (-c)$

$\qquad \tt \rightarrow \: 4 + c$

[ if b is a negative number, it will come out of modulus with a negative sign, to make the overall term out of modulus positive ]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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