Question

HELPP! Algebra 2

If the length of one side of a square is triple and the length of an adjacent side is increased by 10, the resulting rectangle has an area that is 6 times the area of the original square. Find the length of a side pf the original square.

Answer 1

Side = 10 units

Explanation:

Original square area = s x s =s^2

now change the sides and this equals 6s^2

3s * ( s+10) = 6 s^2

3s^2 -30s = 0

s ( 3s-30) = 0 so s = 0 or 10