Answer:
System of linear inequalities is x - y + 1 < 0 and x + 2y +6 < 0
Explanation:
Given:
- The dotted line has two points as (-1,0) and (0,1).
- The solid line also has two points as (-6,0) and (0,-3).
To Find:
- Linear inequality for the system.
Formula used:
- Equation of a line passing through point (x1, y1) and (x2, y2) is given by
- (y-y1) = (y2-y1)/(x2-x1) * (x-x1)
According to question, we have
Inequality for dotted line :
(y-1) > (0-1)/(-1-0) * (x-0)
y - 1 > x
x - y + 1 < 0...(1)
Inequality for solid line:
(y-(-3)) < (0-(-3))/(-6-0) * (x-0)
y + 3 < -x/2
x + 2y +6 < 0...(2)
Using (1) and (2), we get
System of linear inequalities is x - y + 1 < 0 and x + 2y +6 < 0.